This page was translated from Japanese by machine translation. The Japanese page is the original.

Strength Calculation for the Spindle Pulley

A toothed pulley with its shaft bore, key and a torque arrow

Checking whether it's okay to make the 25T motor-side pulley out of aluminum, based on peak torque. Conclusion: Strength is sufficient. Watch out for key play and tooth wear. This is a preliminary calculation, unverified on the actual machine.

Conditions

ItemValueBasis
Peak torque T11.13 N·mA6-RS1000
Rated torque3.18 N·mA6-RS1000
Shaft diameter d19 mmA6-RS1000
Key6×6 (motor side is B6×6×25)A6 manual
Bore-side keyway depth t22.8 mmStandard dimensions for 6×6 (unverified: measure on the actual part)
Engaged key length L20 mmAssuming a pulley width of 20
Pulley25T, 5 mm pitchPlan for a 2:1 reduction ratio
Center distance200 mmAssumed. Used only for calculating the number of engaged teeth

1. Keyway Surface Pressure

Pulley cross section and key

  1. Force on key: F = T ÷ (d ÷ 2) = 11130 N·mm ÷ 9.5 mm = approx. 1172 N
  2. Area bearing the load in aluminum: A = t2 × L = 2.8 × 20 = 56 mm²
  3. Surface pressure: p = F ÷ A = 1172 ÷ 56 = approx. 21 MPa

Since the force was calculated at the shaft surface, the result comes out slightly on the high side.

CaseFp
Rated 3.18 N·m, L 20approx. 335 Napprox. 6 MPa
Peak 11.13 N·m, L 20approx. 1172 Napprox. 21 MPa
Peak 11.13 N·m, width 15 and L 15approx. 1172 Napprox. 28 MPa

Since the exact material is unknown, we assume a conservative yield strength of 100 MPa for aluminum. The safety factor is 100 ÷ 21 = approx. 4.8. For 6061-T6 grade (approx. 240 MPa or higher, typical value), it would be about 11.

2. Shear Stress on the Key Itself

τ = F ÷ (key width × L) = 1172 ÷ (6 × 20) = approx. 10 MPa. Plenty small enough for a steel key.

3. Belt and Tooth Force

Belt forces and engagement

  1. Pitch diameter: 25 × 5 ÷ π = 39.8 mm; for 50T, it is 79.6 mm
  2. Force difference between tight and slack sides: Fe = T ÷ (39.8 ÷ 2) = 11130 ÷ 19.9 = approx. 559 N
  3. Wrap angle: 180° − 2 × asin((79.6 − 39.8) ÷ (2 × 200)) = approx. 168.6°
  4. Number of engaged teeth: 25 × 168.6 ÷ 360 = 11.7, so approx. 11 teeth
  5. If shared equally, per tooth: 559 ÷ 11 = approx. 51 N
  6. Even assuming it's unevenly carried by just 3 teeth: 559 ÷ 3 = approx. 186 N. With tooth height 2 mm (typical value, unverified) × width 20 mm giving 40 mm², that is approx. 4.7 MPa

Wear from chips and dust will become an issue before tooth strength does. The allowable force of the belt itself will be checked in the catalog once the width and brand are decided.

Conclusions and Measures

Comments

No comments yet.

Comments with links, phone numbers or email addresses appear after the site approves them.

Sending needs JavaScript in your browser.

QR code for this page

https://robo100.jp/en/000007